Question

How to colorize even (or odd) table columns using jQuery?
(without adding classes manually)

My markup is:

<table>
   <caption>Table caption</caption>
   <thead>
   <tr><th scope="col">Table header 1</th><th scope="col">Table header 2</th><th scope="col">Table header 3</th><th scope="col">Table header 3</th></tr>
   </thead>
   <tbody>

        <tr><th scope="row">Table row header</th><td>Table data</td><td>Table data</td><td>Table data</td></tr>
        <tr><th scope="row">Table row header</th><td>Table data</td><td>Table data</td><td>Table data</td></tr>
        <tr><th scope="row">Table row header</th><td>Table data</td><td>Table data</td><td>Table data</td></tr>

        <tr><th scope="row">Table row header</th><td>Table data</td><td>Table data</td><td>Table data</td></tr>
   </tbody>
</table>

(it may or may not contain scope attribs or th tags)

Answer 1

You can use the :nth-child() selector for this:

$('table tr :nth-child(2n)').css('background-color', '#eee');

You can see a demo here, this version does the columns, regardless if the cell is a <th> or <td> you can add that in there (e.g. td:nth-child(2n)) if you want to do only one or the other. If you want to select the other columns, just do 2n+1 instead.
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