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Home/ Questions/Q 8292827
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T13:36:42+00:00 2026-06-08T13:36:42+00:00

How to make a controller’s action method containing two different bodyparser? For example, @BodyParser.Of(BodyParser.Json.class)

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How to make a controller’s action method containing two different bodyparser? For example,

@BodyParser.Of(BodyParser.Json.class)
@BodyParser.Of(BodyParser.FormUrlEncoded.class)
public static Result register() {

    RequestBody body = request().body();
    JsonNode node = body.asJson();
    Map<String, String[]> map = body.asFormUrlEncoded();

    if(node != null) {
        return ok("Got: " + node);
    } else if (map != null) {
        return ok("Got: " + map);
    } else {
        return badRequest("Expecting application/json request body");
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T13:36:45+00:00Added an answer on June 8, 2026 at 1:36 pm

    I don’t think it adheres to conventions to allow a single method to parse two different encodings. You basically want two controller functions in one. I think it’s in best taste to have seperate methods handling the different encoding like so

    private static void sharedApplicationLogic() { }
    
    public static Result registerJSON() {
        JsonNode node = request().body().asJson();
        // Parse 
        sharedApplicationLogic();
    }
    
    public static Result registerFD() {
        Map<String,String[]> formdata = request().body().asFormUrlEncoded()
        // Parse
        sharedApplicationLogic();
    }
    

    You can then differentiate between these controller methods in your routes file

    POST /register.json         controllers.Application.registerJSON()
    POST /register.formdata     controllers.Application.registerFD()
    

    (this isn’t pretty RESTfulness, but you get the idea)

    Or by determining this is in a controller function. I find this quite ugly but I guess it’s the answer you’re looking for. The trick is to omit the @BodyParser annotation:

    public static Result register() {
    
        RequestBody body = request().body();
        JsonNode node = body.asJson();
        Map<String, String[]> map = body.asFormUrlEncoded();
    
        if(node != null) {
            return registerJSON(node);
        } else if (map != null) {
            return registerFD(map);
        } else {
            return badRequest("Expecting application/json request body");
        }
    }
    

    As far as I know, there’s no prettier way to do this. There probably shouldn’t be, because you want to map two different methods onto a single one.

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