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Home/ Questions/Q 8178111
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T23:41:08+00:00 2026-06-06T23:41:08+00:00

How would one go about storing positional information in bit fields (the order in

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How would one go about storing positional information in bit fields (the order in which the fields are OR’d or otherwise)?

Background: It popped into my head last night while writing a part of my game engine. Let’s say that we are trying to describe a colour, and as part of that we have the colours that are present in the descriptor (and their order). For example we have the following colour orders on most graphics cards today:

RGBA
BGRA

The following flags can be used to describe colours that are supported:

None = 0x0
A = 0x1
R = 0x2
G = 0x4
B = 0x8

However, by using those fields A | R | G | B is the same thing as B | G | R | A. How would you design the flags and/or operations that can be used to add positional dependence? Bonus marks for adding exclusivity (you can’t have R and G in position 1, for example) and for utility (some clever way that it could be used, possibly in this case scenario).

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  1. Editorial Team
    Editorial Team
    2026-06-06T23:41:09+00:00Added an answer on June 6, 2026 at 11:41 pm

    You can shift the bit field before adding each flag, by the number of bits required for each unique flag. The following flags would be used:

    None = 0x0
    A = 0x1
    R = 0x2
    G = 0x4
    B = 0x8
    Shift = 0x4
    Mask = 0xF (A | R | G | B)
    

    On a little-endian system you would shift it left by Shift (<<) before each OR. The shift left on None can be eliminated because 0 << x = 0. Given the original example:

    A1 = A
    A1R2 = (A1 << Shift) | R
    A1R2G3 = (A1R1 << Shift) | G
    A1R2G3B4 = (A1R1G3 << Shift) | B
    
    B1 = B
    B1G2 = (B1 << Shift) | G
    B1G2R3 = (B1G2 << Shift) | R
    B1G2R3A4 = (B1G2R3 << Shift) | A
    

    To extract the position of each you would repeatedly shift it right (little-endian) and AND it with Mask. Repeating this until the current value reaches None would give you the reverse order.

    let cur = the bit field we want to check
    loop until cur = None:
      let val = cur AND Mask
      emit the name of val
      let cur = cur >> Shift
    

    This does not offer exclusivity (you can easily do a AAGB) and it doesn’t look like it has any utility.

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