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Home/ Questions/Q 8351197
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T08:33:47+00:00 2026-06-09T08:33:47+00:00

http://jsfiddle.net/6Pu3E/ JS: $(document).ready(function() { var block = false; if $(‘#password’).attr(‘disabled’); { block = false;

  • 0

http://jsfiddle.net/6Pu3E/

JS:

$(document).ready(function() {
    var block = false;
    if $('#password').attr('disabled'); {
        block = false;
    }else{
        block = true;
    };
    if block {
        $('.form_input input').attr('disabled','disabled');
    }else{
        $('.form_input input').removeAttribute('disabled');
    }
});

HTML:

<form>
    <input id="password" value="" />
    <input class="form_input" id="Special" />
    <input class="form_input" id="Nothing Special" />
</form>

The goal is that all the inputs with a certain class get the attribute disabled if the first input with ID=”password” does NOT have the attribute disabled. If the first input is disabled, nothing happens. I.e. the other inputs won’t get the disabled attribute.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T08:33:50+00:00Added an answer on June 9, 2026 at 8:33 am

    Like this? jsFiddle example

    var block = false;
    if ($('#password').attr('disabled')) {
        block = false;
    } else {
        block = true;
    }
    if (block) {
        $('.form_input').attr('disabled', 'disabled');
    } else {
        $('.form_input').removeAttribute('disabled');
    }
    

    ​Or the ultra-condensed version:

    $('.form_input').attr('disabled',!$('#password').attr('disabled') );​
    

    jsFiddle example

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