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Home/ Questions/Q 8300441
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T16:33:48+00:00 2026-06-08T16:33:48+00:00

I am a newbee in cherrypy. I just tried with a sample program of

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I am a newbee in cherrypy.
I just tried with a sample program of wsgiserver.The program is as follows

from cherrypy import wsgiserver

def my_crazy_app(environ, start_response):
  status = '200 OK'
  response_headers = [('Content-type','text/plain')]
  start_response(status, response_headers)
  return ['Hello world!']

server = wsgiserver.CherryPyWSGIServer(
        ('127.0.0.1', 8080), my_crazy_app,
        server_name='localhost')
server.start()

I got the output Hello world successfully,
but the problem is when i hit Ctrl-c on the terminal to stop the server, its not getting stopped. How to do it?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T16:33:49+00:00Added an answer on June 8, 2026 at 4:33 pm

    IIRC, the wsgiserver itself is not associated to any signal and therefore doesn’t respect the SIGINT interruption.
    Only the higher level CherryPy engine will provide that. If you can’t use it, you probably want to
    install a handler using the Python signal module.

    Well, something along those lines will do the job:

    import signal
    
    from cherrypy import wsgiserver 
    def my_crazy_app(environ, start_response): 
       status = '200 OK' 
       response_headers = [('Content-type','text/plain')] 
       start_response(status, response_headers) 
       return ['Hello world!'] 
    
    server = wsgiserver.CherryPyWSGIServer( ('127.0.0.1', 8080), my_crazy_app, server_name='localhost')
    
    def stop_server(*args, **kwargs):
      server.stop()
    
    signal.signal(signal.SIGINT,  stop_server)
    
    server.start()
    
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