Question

I am attempting Problem 20 on Project Euler and this is the solution that I have so far:

import re
mylist = []
var1 = 100
def exclamation(n, L):
    for n in xrange(1, (n)):
        L.append(n)
        n -= 1
    print L
def multiply(L, V):
    while len(L) > 0:
        V = L.pop(-1) * V
    print V
exclamation(100, mylist)
multiply(mylist, var1)
print mylist
list1 = re.findall('.', var1)
print list1

However, re.findall only takes strings, and I was wondering if there was something else that did the same job or an escape character to tell it that it is a variable.

I have tried putting a “/” in front of it as well as “/escape” which I think I found on the python documentation, however it didn’t work.

Answer 1

It’s not about whether it’s a variable or not. It’s about whether or not it’s a string. Just make the argument a string. If var1 is an int, this is very easy:

re.findall('.', str(var1))