I am attempting to reformat the data set my.data to obtain the output shown below the my.data2 statement. Specifically, I want to put the last 4 columns of my.data on one line per record.id, where the last four
columns of my.data will occupy columns 2-5 of the new data matrix if group=1 and columns 6-9 if group=2.
I wrote the cumbersome code below, but the double for-loop is causing an error that I simply cannot locate.
Even if the double for-loop worked, I suspect there is a much more efficient way of accomplishing the
same thing – (maybe reshape?)
Thank you for any help correcting the double for-loop or with more efficient code.
my.data <- "record.id group s1 s2 s3 s4
1 1 2 0 1 3
1 2 0 0 0 12
2 1 0 0 0 0
3 1 10 0 0 0
4 1 1 0 0 0
4 2 0 0 0 0
8 2 0 2 2 0
9 1 0 0 0 0
9 2 0 0 0 0"
my.data2 <- read.table(textConnection(my.data), header=T)
# desired output
#
# 1 2 0 1 3 0 0 0 12
# 2 0 0 0 0 0 0 0 0
# 3 10 0 0 0 0 0 0 0
# 4 1 0 0 0 0 0 0 0
# 8 0 0 0 0 0 2 2 0
# 9 0 0 0 0 0 0 0 0
Code:
dat_sorted <- sort(unique(my.data2[,1]))
my.seq <- match(my.data2[,1],dat_sorted)
my.data3 <- cbind(my.seq, my.data2)
group.min <- tapply(my.data3$group, my.data3$my.seq, min)
group.max <- tapply(my.data3$group, my.data3$my.seq, max)
# my.min <- group.min[my.data3[,1]]
# my.max <- group.max[my.data3[,1]]
my.records <- matrix(0, nrow=length(unique(my.data3$record.id)), ncol=9)
x <- 1
for(i in 1:max(my.data3$my.seq)) {
for(j in group.min[i]:group.max[i]) {
if(my.data3[x,1] == i) my.records[i,1] = i
# the two lines below seem to be causing an error
if((my.data3[x,1] == i) & (my.data3[x,3] == 1)) (my.records[i,2:5] = my.data3[x,4:7])
if((my.data3[x,1] == i) & (my.data3[x,3] == 2)) (my.records[i,6:9] = my.data3[x,4:7])
x <- x + 1
}
}
You are right,
reshapehelps here.Comparison: