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Home/ Questions/Q 8335467
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T03:41:09+00:00 2026-06-09T03:41:09+00:00

I am busy with a practical. I have to enter a string or a

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I am busy with a practical. I have to enter a string or a message and have to convert it to Morse code:
‘A’ = .-
‘B’ = -…
ecs.

I can do that with no problem by using a series of if statements.

for(int i = 0;i < stringvalue.length();i++)
{
    if(stringvalue == 'A')
        cout << ".-";
        //there is 26 if statements

}

But when i enter a string, eg.

"Testing data"

Only the first part of the string is converted(test is converted) to Morse.

Why does it not convert the part after the space. If there is a space in the string it must output “/ “.

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  1. Editorial Team
    Editorial Team
    2026-06-09T03:41:09+00:00Added an answer on June 9, 2026 at 3:41 am

    If your input routine looks like this:

    std::string input;
    std::cin >> input;
    

    The input is read up to the first whitespace character. To read the whole line, you can use std::getline.

    std::getline(std::cin, input);
    
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