Question

I am busy with a task and i have to create a structure and with that structure i have to create and delete an object.

Here is how i created the struct with a function inside.

struct Operation
{
    char op;
    double (*apply)(Operation*, double,double); // takes two doubles
}

That i perfectly understand. Now the object must be created.

Operation* Make(char op)
{
    Operation* ret = new Operation;
    ret -> op = op;
    ret -> apply = doit;//doit is a norther function 
    return ret;
}

I know the “->” operatic is the same as saying:

(*ret).op = op;

And the delete object;

void BrakeObject(Operation& o)
{
    delete o;
    o = NULL;
}

Will the function (apply) look the same as a basic function?
Is this a array?

 Operation* ret = new Operation;

What is the object is it just a function?

Answer 1

Seems that your vision does not match the task…

A)The structure
char op; can not be an “object”. it is a “value”, hm…
but char *op; may be ok?

B) Array.

Operation* ret = new Operation; //is this a array?

Nope. you have created a pointer to single value.

C) operator. this is wrong syntax

(*ret) op = op;

this will be ok

(*ret).op = op;

D) delete

void break(Operation& o)

it is wrong syntax, this will be ok

void BrakeObject(Operation*& o)
{
  delete o;
  o = NULL;
}