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Home/ Questions/Q 8343391
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T06:02:53+00:00 2026-06-09T06:02:53+00:00

I am confused about the functionality of void operator()() . Could you tell me

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I am confused about the functionality of void operator()().

Could you tell me about that, for instance:

class background_task
{
public:

    void operator()() const
    {
        do_something();
        do_something_else();
    }
};

background_task f;

std::thread my_thread(f);

Here, why we need operator()()? What is the meaning of the first and second ()? Actually, I know the operation of normal operator, but this operator is confusing.

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  1. Editorial Team
    Editorial Team
    2026-06-09T06:02:55+00:00Added an answer on June 9, 2026 at 6:02 am

    The first () is the name of the operator – it’s the operator that is invoked when you use () on the object. The second () is for the parameters, of which there are none.

    Here’s an example of how you would use it:

    background_task task;
    task();  // calls background_task::operator()
    
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