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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T11:41:05+00:00 2026-06-08T11:41:05+00:00

I am currently dealing with numbers with different bases. I am using the function

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I am currently dealing with numbers with different bases. I am using the function Long.parseLong to convert a number from base int to its decimal value:

Long.parseLong(“A”, 16) to convert A which is a hexadecimal to its decimal value 10. I then use Long.toString(10, 16) to convert it back to A.

The problem now is that one of the entries in the problem set is “AAAAAAAAAAAAAAAAAAA” and when I use the Long.parseLong(); function, it returns an error because the size of the conversion can’t fit to a Long. I tried to use Float, but I’m afraid that there is no Float.parseFloat(String, int) with the int as its radix.

Is there an alternative which I can use?
BigInteger also doesn’t have any parse function with the radix.

Any help will be much appreciated.

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  1. Editorial Team
    Editorial Team
    2026-06-08T11:41:08+00:00Added an answer on June 8, 2026 at 11:41 am

    BigInteger has a constructor, which does radix conversion for you:

    BigInteger num = new BigInteger("AAAAAAAAAAAAAAAAAAA", 16);
    

    If you wish to convert back to hexadecimal, you can use toString:

    String hex = num.toString(16);
    
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