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Home/ Questions/Q 8246445
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T22:30:28+00:00 2026-06-07T22:30:28+00:00

I am currently getting a file list from an OpenFileDialog and adding then into

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I am currently getting a file list from an OpenFileDialog and adding then into a list this way

private void BtnSelect_Click(object sender, RoutedEventArgs e)
        {
            OpenFileDialog Open = new OpenFileDialog();
            Open.Filter = "RIFF/RIFX (*.Wav)|*.wav";
            Open.CheckFileExists = true;
            Open.Multiselect = true;
            Open.ShowDialog();

            LstFile.Items.Clear();
            foreach (string file in Open.FileNames)
            {
                LstFile.Items.Add(file);


            }
        }

How would i Get the individual file names from the list and pass them into cmd.exe

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T22:30:30+00:00Added an answer on June 7, 2026 at 10:30 pm

    Here’s how to make a process with arguments

            Process p = new Process();
            p.StartInfo.FileName = "cmd";
            p.StartInfo.Arguments = "arg1 arg2";
            p.StartInfo.UseShellExecute = false;
    
            p.Start();
            p.WaitForExit();
    

    just pass whatever arguments you want to pass in place of arg1 and arg2

    If you need to know how to get output from the process, just say so and I’ll include that too.

    you can get individual filenames by iterating over your list, just use a foreach loop

    foreach(string fn LstFile.Items)
    {
        //do something with fn
    }
    
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