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Home/ Questions/Q 8319659
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T22:23:46+00:00 2026-06-08T22:23:46+00:00

I am currently trying to find I solution that will not let a value

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I am currently trying to find I solution that will not let a value exceed a certain value, in this case, 0x1000 (4096). This is an easy solution, but the key here is speed.

int someVal = rand();
for(int i = 0; i < 10000; i++)
{
    if(someVal > 0x1000)
        someVal = 0x1000;
    cout << someVal;
    someVal = rand();
}

That is too slow, unless of course there is no other way to do it. Thanks for any help, Hetelek.

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  1. Editorial Team
    Editorial Team
    2026-06-08T22:23:48+00:00Added an answer on June 8, 2026 at 10:23 pm

    Could try this;

    floatValue = floor(floatValue * 0x1000 + 0.5)/0x1000; 
    
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