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Home/ Questions/Q 971517
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T02:58:40+00:00 2026-05-16T02:58:40+00:00

I am declaring an array using new int *a = NULL; a = new

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I am declaring an array using new

int *a = NULL;
a = new int[10];

a[0] = 23;
a[1] = 43;
a[2] = 45;
a[3] = 76;
a[4] = 34;
a[5] = 85;
a[6] = 34;
a[7] = 97;
a[8] = 45;
a[9] = 22;

PrintElements(a, 10);

void PrintElements(int * array, int size){
    for (int i=0; i<size; i++) {
        cout << endl << array[i];
    }
}

Now when I print the values I am getting these values

17
2b
2d
4c
22
55
22
61
2d
16

Can somebody tell me what am I doing wrong…?
On the other hand when I dont use new & initialize array without it everything works fine.

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  1. Editorial Team
    Editorial Team
    2026-05-16T02:58:40+00:00Added an answer on May 16, 2026 at 2:58 am

    You may have written a std::hex to the cout at some point; that will remain in effect until overridden.

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