Question

I am developing an website in php where user can upload csv file. after clicking ‘upload’ button, file is renamed and saved in the format ‘upload’.time(). I need to show the contents of the uploaded file just after uploading the file.
So far I have been able to upload file correctly and I have tested with a static filename and have been able to read csv file perfectly. but when I am trying to get recently uploaded file name just after uploading I am not getting anywhere. searched through the whole site but didn’t get any solution that worked for me.
I am using codeigniter 2.1.0 .

Controller file:

<?php     
class Csv_ci extends CI_Controller {

function is_logged() {
    $is_logged_in = $this->session->userdata('is_logged_in');
    if (!isset($is_logged_in) || $is_logged_in != true)
        return false;
    else
        return true;
}

function index() {
    if ($this->is_logged() == TRUE) {
        $this->load->model('Csv_model');

        if ($this->input->post('upload')) {
            $name = $this->Csv_model->do_upload();
            //print_r($name);
            if (isset($name)) {
                $filePath = "localhost/map_ci/csv/" . $name;
                //$filePath = './csv/bank_data.csv';
                $row = 1;
                if (($handle = fopen($filePath, "r")) !== FALSE) {
                    while (($data = fgetcsv($handle, 0, ",")) !== FALSE) {
                        $num = count($data);

                        $file_data[$row]['district_name'] = $data[1];
                        $file_data[$row]['bank_name'] = $data[2];
                        $file_data[$row]['area_name'] = $data[3];
                        $file_data[$row]['address'] = $data[4];
                        $row++;
                    }

                    fclose($handle);
                }
                $this->load->view('csvshow', array('file_data' => $file_data));
            }
        }
    }
    else $this->load->view('invalid_member');
     }
}

Model file:

 <?php

class Csv_model extends CI_Model {

var $gallery_path;
var $gallery_path_url;

function Csv_model() {
    parent::__construct();


    $this->gallery_path = realpath(APPPATH . '../csv');
    $this->gallery_path_url = base_url() . 'csv/';
}

function do_upload() {
    $config = array(
        'upload_path' => $this->gallery_path,
        'allowed_types' => 'text/csv|csv|text/x-comma-separated-values|text/comma-separated-values|application/x-csv|text/x-csv|text/csv|application/csv|',
        'max_size' => '5000',
        'file_name' => 'upload' . time()
    );


    $this->load->library('upload', $config);

    if (!$this->upload->do_upload())
        echo $this->upload->display_errors();
    else {
        $file_info = $this->upload->data();
        $csvfilepath = "csv/" . $file_info['file_name'];
        $this->addfromcsv($csvfilepath);
        $filename = $file_info['file_name'];
        // print_r($filename);
        return $filename;
    }
} 
}

to retrieve file name I am doing file_info['file_name'].
Please help me find a solution.

Update:
My current problem has been solved after removing $csvfilepath = "csv/" . $file_info['file_name'];
$this->addfromcsv($csvfilepath); these two lines from my code.Now its returning uploaded file name.yet to check whether fully working or not.

Update 2: code functioning well
thanks all for your help.

Answer 1

You can return the concatenation of $config['upload_path'] & $config['file_name'] from do_upload() and use it to read the corresponding file.