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I am executing a java-synchronisation example:
Thread call code:
Caller ob1 = new Caller(target, "Hello");
Caller ob2 = new Caller(target, "Synchronized");
Caller ob3 = new Caller(target, "World");
Output:
[Hello] [World] [Synchronized]
Why does “Synchronized” gets printed last, though it’s called in 2nd?
There’s no guarantee in the order of execution. It is the discretion of the JVM.
Invoking the start() method of a Thread instance doesn’t guarantee that it will run after the method call right away.