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Home/ Questions/Q 952513
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T23:54:20+00:00 2026-05-15T23:54:20+00:00

I am generating a dropdown on a completely separate page by jquery append function.

  • 0

I am generating a dropdown on a completely separate page by jquery append function. I was getting duplicate rows of data if I just use append

  if(params.totalRecords > 50){
         var i, j;
    j = 0;              
    for(i=0; i < params.totalRecords; i++){                 
    if(i%50==0){
    $('#startRecord').append( 
    $('<option></option>').val(i).html((j+1)+'-'+(j+=50)));          
    }
  }             
    $('#dropDownSpan').css('visibility', 'visible'); 
}  

so now when I was adding the values to drop down it was adding duplicate rows like this

<option value=0>1-50</option>
<option value=50>51-100</option>
<option value=0>1-50</option>

depending what option I would choose, it would just make it duplicate.

Now to avoid that I did the following

  if(params.totalRecords > 50){
    $('#startRecord').val(0).html("1-50");
    var i, j;
    j = 0;              
    for(i=0; i < params.totalRecords; i++){                 
    if(i%50==0){
    $('#startRecord').append( 
    $('<option></option>').val(i).html((j+1)+'-'+(j+=50)));          
    }
  }             
    $('#dropDownSpan').css('visibility', 'visible'); 
}    

Now the problem is that it alway restes it to 1-50 records cause of

$('#startRecord').val(0).html("1-50");

How could I show the last selected one there.
thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T23:54:20+00:00Added an answer on May 15, 2026 at 11:54 pm

    solved it using this var i, j=0, y=0; //check how manyblock of 50s we have. 1 per 50 records. Last block doesnt have to have all 50 for(r=0; r

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