Question

I am getting server error for this script. I am assuming the SQL is not correctly syntaxed but i have tried everything I could think of and researched thoroughly. I’m sure this is just a novice, naive mistake but any advice will be appreciated.

function updateLogout($userID) {
    $success = false;
    //  Get current date-time in MySQL format
    $nowTimeStamp = date("Y-m-d H:i:s");
    $insertLogout_SQL = "UPDATE AccessLog SET";
    $insertLogout_SQL .= " timeLogout='".$nowTimeStamp."'";
    $insertLogout_SQL .= " WHERE userID='".$userID."'";

    if (mysql_query($insertLogout_SQL)) {
        $success = true;
    } else {
        $success = $insertLogout_SQL . "<br />" . mysql_error();
    }
    return $success;
}

Answer 1

Following on from @Matt’s answer:

function updateLogout($userID) {
    $success;
    $insertLogout_SQL = "UPDATE `AccessLog` SET `timeLogout`= NOW() WHERE userID = '$userID'";

    if (mysql_query($insertLogout_SQL))
        $success = true;
    else
        $success = $insertLogout_SQL . "<br />" . mysql_error();
    return $success;
}

Also, you should really be using mysqli_query.