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Home/ Questions/Q 8310011
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T19:18:23+00:00 2026-06-08T19:18:23+00:00

I am getting wrong result using below method. public double evaluate(final double leftOperand, final

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I am getting wrong result using below method.

public double evaluate(final double leftOperand, final double rightOperand) {
        Double rtnValue = new Double(leftOperand * rightOperand);
        return rtnValue.doubleValue();
    }

Enter Parameter value are: leftOperand= 100 and rightOperand=2.55

I am getting Wrong answer: 254.99999999999997

The correct answer is a 255.0

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  1. Editorial Team
    Editorial Team
    2026-06-08T19:18:25+00:00Added an answer on June 8, 2026 at 7:18 pm

    Use BigDecimal

    BigDecimal bd = new BigDecimal("100");
    BigDecimal ans = bd.multiple(new BigDecimal("2.55"));
    System.out.println(ans);
    

    See Also

    • Working IDE One demo

    • Retain precision with double in Java

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