Question

I am looking for the perfect 1 line regex pattern to block a huge list of porn star names using my content blocking software.

The software is fully regex-compliant, and will accept any well-written regex.

As an example, here is a line of those I currently use – the lines are identical somehow where the first blocks everything starting with, and the second blocks everything ending with my list of predefined words.

(\b(cohf|cock(s)?|cum(s)?|cutie(s)?|creamy(-)?pie(s)?))(-)?\w+\b
\w+(-)?((cam(s)?|cohf|cock(s)?|cum(s)?|cutie(s)?|creamy(-)?pie(s)?)\b)

Now, I have a list that looks like:

**pornstar1 name**
pornstar2 name
pornstar3 name
some-other name-here

I would like the offered regex to block ANY/ALL URL’s, where the two parts of the name appear – Examples:

• http://www.alink-to-pornstar1.com <– not blocked (only a part pf the
  name is here)
• http://www.alink-to-pornstar1-name.com <– blocked (has
  the two parts)

Thank you in advance

Answer 1

1. Take url and remove all [^a-zA-Z] – replace them by empty string
2. Take list of all not allowed words or phrases and do same as (1)
3. With such list now join all keywords with | character to one regex string
4. Check if this regex match url you modified at (1)

Having variables url and list, one-line jQuery solution would be:

url.replace(/[^a-z]/gi,'').match(new RegExp("("+$.map(list,function(e){return e.replace(/[^a-z]/gi,'');}).join('|')+")"))!=null

with result being true if url contains some of the restricted words or phrases from the list.