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Home/ Questions/Q 8178849
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T23:51:56+00:00 2026-06-06T23:51:56+00:00

I am lost. I have a class Editor and a class Controller . Classes

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I am lost. I have a class Editor and a class Controller. Classes WorkflowEditor and WorkflowController derive from Editor and Controller respectively. Class Controller has a protected member Editor editor and class WorkflowController has a private member WorkflowEditor editor (with same name).


Edit from EitanT:
Here’s a simplified code snipped to illustrate what the OP has described:

class Controller
{
    Editor editor;
    // ...
}

class WorkflowEditor : public Editor {
    // ...
};

class WorkflowController : public Controller {
    WorkflowEditor editor;
    // ...
};

My application is a module with graphical interface. In workflow mode, a ribbon appears on Launch, and a wizard is displayed. On click on one button, a method in class Controller is called. Execution crashes because at this time, Editor editor class member of object with type Controller is dead. I would like class member Editor editor to be the same as class member WorkflowEditor editor (same name).

In other words, if a class A has a member of class B and class childA (derived from A) has a member of class childB (derived from B), and member of type childB and B have same name, isn’t the member “inherited”?

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  1. Editorial Team
    Editorial Team
    2026-06-06T23:51:58+00:00Added an answer on June 6, 2026 at 11:51 pm

    The object is inherited, but is not the same object as the one declared in the derived class. The derived class member is a separate object to the base class member, even though they have the same name. Technically, it hides the base class member, making it accessible only with its qualified name, Controller::editor.

    You can achieve what you want with a virtual function, which you override in the derived class to access an object contained there:

    class Controller {
    public:
        // No data members, just an abstract interface
    
        // Access a data member of the derived class
        virtual Editor & editor() = 0;
        virtual ~Controller() {}
    };
    
    class WorkflowController : public Controller {
    public:
        WorkflowEditor & editor() {return editor_;}
    
    private:
        // The object itself - accessible as its true type here, or
        // as its abstract type via the abstract interface.
        WorkflowEditor editor_;
    };
    
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