Question

I am playing around with this:

$sort = array('t1','t2');

function test($e){
    echo array_search($e,$sort);
}

test('t1');

and get this error:

Warning: array_search(): Wrong datatype for second argument on line 4

if I call it without function like this, I got the result 0;

echo array_search('t1',$sort);

What goes wrong here?? thanks for help.

Answer 1

Variables in PHP have function scope. The variable $sort is not available in your function test, because you have not passed it in. You’ll have to pass it into the function as a parameter as well, or define it inside the function.

_{You can also use the global keyword, but it is really not recommended. Pass data explictly.}