Question

I am probably missing something simple here but I feel it best to ask anyway.

I have the following code:

$newarray = json_decode($jsoncode);
$rad = 24;
foreach ($newarray->objname as $obj)
{
    echo "<map name='" . $mapname . "'>";
    echo "<area shape=\"circle\" coords='" . $obj->x . "," . $obj->y . "," . $rad . "' alt='" . $obj . "'>";
    echo '</map>';
}

coming from a manually created json string:

$jsoncode = '{"objname":{"Forest 1":{"x":120,"y":120},"Forest 2":{"x":434,"y":225}}}';

I am getting an error when trying to call the $obj variable to use within the foreach. Is there like something I have to add to make it show the name stored in the variable?

P.S. I have no problem with the rest of the code

Answer 1

PHP’s foreach syntax should be like this –

foreach ($array AS $key=>$object){ 
  ... 
}

So your code should look like this –

foreach ($newarray AS $objectName => $obj)

• $objectName is the index in $newarray.
• $obj is the actual element from the array.

---

http://php.net/manual/en/control-structures.foreach.php

The documentation has this to say about the syntax of the foreach statement –

foreach (array_expression as $value)
statement
foreach (array_expression as $key => $value)
statement