Question

I am trying to achieve a check with the if...else statement that only squares the odd numbers between 100 and 150, otherwise the number is just printed.

How can I revise my if statement to achieve this please? An educated guess is that an operator or combination of operators are used.

 for (i=100; i<=150; i++)
    {
        if (i === 0)
        {
            console.log(i * i);
        }
        else
        {
            console.log(i);
        }
    }

Answer 1

The operator you are looking for is %:

for(i = 100; i <= 150; i++) {
    if(i % 2 === 1) { // It's odd
        console.log(i * i);
    } else {
        console.log(i);
    }
}

a % b is basically the remainder obtained when a is divided by b. It’s called the modulus operator.