Question

I am trying to call OpenCV function MinAreaRect2 from within python.
I use OpenCV 2.4.2 with python 2.7 and numpy 1.6.
I went this far :

import cv

def nda2ipl(arr, dtype=None):
    return cv.fromarray(np.ascontiguousarray(arr, dtype=dtype))

def min_area_rect2(points):
    storage = cv.CreateMemStorage()
    cv_points = nda2ipl(points.reshape((-1, 1, 2)))
    out = cv.MinAreaRect2(cv_points, storage)
return out

I can call this function with a ndarray of shape (N x 2). I get this kind of results :

((476.5, 604.5), (951.0, 1207.0), -0.0)

I assume that the first tuple is the center of the box, the second gives the width and the height and the last is the angle.

The problem is I could not get a clear reference stating this. Actually, the opencv documentation tells me what the functions returns in Python.

I found the official documentation about this function but this is not very helpful.

What are exactly the output of MinAreaRect2 in python ?
More generally, where do you get precise documentation about the OpenCV python wrapper ?

Answer 1

OpenCV Python wrapper documentation is kept along with the normal documentation in same site, http://www.docs.opencv.org

Earlier Python module used was cv interface, which used native data types from original C++ interface like cvMat, cvSeq etc.

Later it was shifted to more better, advanced and simpler module cv2 interface. In it, everything is returned as either Numpy arrays or native python data types.

Here, tuple returned has the same arguments as that of cvBox2D. You can find more details the differences between different python wrappers here : What is different between all these OpenCV Python interfaces?

Here, your assumption is correct. Those values specified exactly what you mentioned.

If you want to draw rotated rect, you need 4 vertices of the rectangle. For that, you need a function which is never seen in documentation, ie cv2.cv.BoxPoints() (but don’t worry, it will be there in documentation when OpenCV 2.4.3 is released. )