Question

I am trying to communicate with Facebook doing simple things. At the moment I can log a user in and post to their wall as them. But for whatever reason, I can’t seem to access public information such as their name. I consistently get this error:

{“error”:{“message”:”Syntax error \”Expected end of string instead of \”?\”.\” at character 4: name?access_token=MYACCESSTOKEN”,”type”:”OAuthException”,”code”:2500}}

Here is the call:

SampleRequestListener srl = new SampleRequestListener();
AsyncFacebookRunner afr = new AsyncFacebookRunner(facebook);
afr.request("http://graph.facebook.com/me?fields=name", (RequestListener)srl);

That call is made within a validated session (in the onComplete portion of the DialogListener for .Authorize). Using my access_token and the exact same string as above I can get the request to work just fine at http://developers.facebook.com/tools/explorer/

The error occurs whilst parsing the response in the RequestListener.onComplete

JSONObject json = Util.parseJson(response);
final String name = json.getString("name");
System.out.println("Hi, my name is " + name);

Thank you for your time. All input is welcomed.

UPDATE *

There are two things going on. In the facebook API, Util.openUrl was appending a “?” between the field name and the access_token (as the answer below pointed out). This seems odd. I wonder if I pulled an old version of the API or something. You would think that would be set up correctly.

Also, I called the method incorrectly:
This:

afr.request("http://graph.facebook.com/me?fields=name", (RequestListener)srl);

Should be:

afr.request("me?fields=name", (RequestListener)srl);

Answer 1

Looks like the actual request being sent is something like

/me?fields=name?access_token=MYACCESSTOKEN

and that of course is wrong; it should be an ampersand before the second parameter and not a question mark.

You’d have to look for the location in the code where the access token is added as parameter. At that point there should be a check for whether this URL already contains a question mark or not before appending the access_token parameter.