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Home/ Questions/Q 8284295
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T11:03:13+00:00 2026-06-08T11:03:13+00:00

I am trying to create a batch file that renames all the files in

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I am trying to create a batch file that renames all the files in the folder by its name and created date. For example >User file name change it to >User_13-06-2012. Please help me.

I have this code which just add the new date with the name.

@echo off
cd "C:\account folder"
for /f "tokens=1-3 delims=/" %%a in ('echo %date%') do set today=%%a%%b%%c
for %%f in (*.*) do ren "%%f" "%%~nf_%today%%%~xf"

Thanks from now.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T11:03:14+00:00Added an answer on June 8, 2026 at 11:03 am

    Edited: previous answer was incorrectly showing modification time, not creation time.

    This

    @echo off
    for %%A in (*.*) do ( 
      for /f "skip=7" %%B  in ('dir /T:c "%%A"^|sort') do (
       for /f "tokens=1-3 delims=/" %%C in ("%%B") do echo %%~nA_%%C-%%D-%%E%%~xA
      )
    )
    

    will spit out new names for your files formatted as per your req. Should it fairly easy to work from this.

    Note: This assumes your date separator is ‘/’ and in general it’s locale dependent

    Edit: as pure batch solution above is inherently unreliable below is equivalent powershell one liner – it’s faster, locale independent and easy to modify. I would recommend to use this instead if ps is available.

    get-childitem | ? {$_ -is [IO.FileInfo]} | foreach-object {$_.basename + "_" + (get-date ($_.CreationTime) -uformat "%d-%m-%Y") + $_.extension}
    
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