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Home/ Questions/Q 781201
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T20:11:46+00:00 2026-05-14T20:11:46+00:00

I am trying to declare an array in bash, but when the code is

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I am trying to declare an array in bash, but when the code is run it says it cannot find the array. I have tried to write out the declaration of the array in several different ways, but it seems no matter how I try to declare it I cannot get it to work. I originally tried to declare it as such:

candidate[1]= 0
candidate[2]= 0
candidate[3]= 0

The error messages that are returned are:

votecalculation.sh: 13: candidate[1]=: not found
votecalculation.sh: 14: candidate[2]=: not found
votecalculation.sh: 15: candidate[3]=: not found

After this I tried another solution I found online:

ARRAY=( 'can1' 'can2' 'can3' )

When that is used it returns this error:

votecalculation.sh: 12: Syntax error: "(" unexpected

I am new to Bash and am getting really confused about arrays. Is there some specific way I need to declare an array or am I just going about it completely wrong?

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  1. Editorial Team
    Editorial Team
    2026-05-14T20:11:46+00:00Added an answer on May 14, 2026 at 8:11 pm
     #!/bin/bash
    
     myarray[0]=hello
     myarray[1]=world
    
     echo "${myarray[0]}"
     echo "${myarray[1]}"
    

    save that to helloworld.bash and chmod +x the file.

    execute using
    ./helloword.bash

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