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Home/ Questions/Q 6178267
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T00:25:40+00:00 2026-05-24T00:25:40+00:00

I am trying to make a generator function that yields an item on each

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I am trying to make a generator function that yields an item on each call, however I keep getting the same item. Here is my code:

  1 from pymongo import Connection
  2 
  3 connection = Connection()
  4 db = connection.store
  5 collection = db.products
  6 
  7 def test():
  8         global collection #using a global variable just for the test.
  9         items = collection.find()
  10        for item in items:
  11                 yield item['description']
  12        return
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  1. Editorial Team
    Editorial Team
    2026-05-24T00:25:40+00:00Added an answer on May 24, 2026 at 12:25 am

    First of all, remove return, it’s not necessary.

    Your problem isn’t with test() but how you’re calling it. Don’t just call test().

    Do something like:

    for item in test():
        print item
    

    And you’ll get one item at a time. What this is doing is basically:

    from exceptions import StopIteration
    it = iter(test())
    
    while True:
        try:
            item = it.next()
        except StopIteration:
            break
        print item
    
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