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Home/ Questions/Q 614037
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:04:07+00:00 2026-05-13T18:04:07+00:00

I am trying to print out an array of integers. I am getting a

  • 0

I am trying to print out an array of integers. I am getting a seg fault when I try to print as below. If I uncomment the “In for loop” it will print everything except the last item of the array and it still has a seg fault. When I uncomment both of the comments (or just the “done with for loop”) everything prints fine. Why does this happen and how do I fix it?

for( int i = 0; i < l.usedLength; i++ )
{
    //cout << "**********In for loop" << endl;
    cout << l.largeInt[ i ];
}
//cout << "**********done with for loop" << endl;

Here is the whole class:

#include "LargeInt.h"
#include <ctype.h>

LargeInt::LargeInt()
{
    usedLength = 0;
    totalLength = 50;

    largeInt = new int[totalLength];
    for( int i=0; i<totalLength; i++ )
    {
        largeInt[i] = 0;
    }
}

LargeInt LargeInt::operator+(const LargeInt &l) const
{}

LargeInt LargeInt::operator-(const LargeInt &l) const
{}

LargeInt LargeInt::operator*(const LargeInt &l) const
{}

LargeInt LargeInt::operator/(const LargeInt &l) const
{}

bool LargeInt::operator==(const LargeInt &l) const
{}

ostream& operator<<(ostream &out, const LargeInt &l)
{
    cout << "In output" << endl;

    if( l.usedLength == 0 )
    {
        cout << 0;
    }
    else
    {
        cout << "In else... NON 0" << endl;

        for( int i = 0; i < l.usedLength; i++ )
        {
            cout << "In for loop" << endl;
            cout << l.largeInt[ i ];
        }
        //cout << "done with for loop" << endl;
    }
    //cout << "after the if.... all done with output" << endl;
}

istream& operator>>(istream &in, LargeInt &l)
{
    char x;
    while (std::cin.get(x) && x >= '0' && x <= '9')
    {
        l.largeInt[ l.usedLength ] = x-48;
        l.usedLength++;
        //need to check array length and make bigger if needed
    }

}

Main:

#include <stdlib.h>
#include <iostream>

#include "LargeInt.h"

int main(int argc, char** argv) {

    cout << "\nJosh Curren's Assignment #5 - Large Integer\n" << endl;

    LargeInt lint;

    cout << "Enter a large int: ";
    cin >> lint;

    cout << "\nYou entered: " << endl;
    cout << lint << endl;
    cout << endl;


    return (EXIT_SUCCESS);
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T18:04:07+00:00Added an answer on May 13, 2026 at 6:04 pm

    You forgot the last line in ostream& operator<<(ostream &out, const LargeInt &l):

    return out;
    

    With this line it works perfectly.

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