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Home/ Questions/Q 6719041
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T09:02:44+00:00 2026-05-26T09:02:44+00:00

I am trying to use .ajaxSubmit(). I want to pass it the options object.

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I am trying to use .ajaxSubmit(). I want to pass it the options object. I want to create this options object based on the user’s behavior. So this is how I am doing it:

$('#my-form').ajaxSubmit(GetSearchAjaxFormOptions(param1, param2));

function GetSearchAjaxFormOptions(param1, param2) {
    return { target: '#results',
        data: GetData(),
        success: RunAfterAjaxSubmit(param1, param2)
    };
}

function RunAfterAjaxSubmit(param1, param2) {
    //    do stuff
}

Everything works fine except that RunAfterAjaxSubmit is called not only after the ajax call returns, but also before the ajax call is made at the following line:

success: RunAfterAjaxSubmit(param1, param2)

How do I change my code so it is only called after the ajax call is returned.

Many Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T09:02:45+00:00Added an answer on May 26, 2026 at 9:02 am

    changing the success line to:

    success: function () { RunAfterAjaxSubmit(param1, param2)}
    

    fixes the problem

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