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Home/ Questions/Q 5988981
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Editorial Team
  • 0
Editorial Team
Asked: May 22, 20262026-05-22T23:02:09+00:00 2026-05-22T23:02:09+00:00

I am trying to write a simple program for this interview question: Write a

  • 0

I am trying to write a simple program for this interview question:

Write a function that checks for valid unicode byte sequence. A unicode
sequence is encoded as: – first byte indicates number of subsequent bytes
‘11110000’ means 4 subsequent data bytes – data bytes start with a
’10xxxxxx’

   public static void main(String[] args)
{

        System.out.println(checkUnicode(new byte[] {(byte)'c'}));

}

    /**
     * Write a function that checks for valid unicode byte sequence. A unicode
     * sequence is encoded as: - first byte indicates number of subsequent bytes
     * '1111000' means 4 subsequent data bytes - data bytes start with a
     * '10xxxxxx'
     * 
     * @param unicodeChar
     * @return
     */
 public static boolean checkUnicode(byte[] unicodeChar)
{
    byte b = unicodeChar[0];
    int len = 0;

    int temp = (int)b<<1;
    while((int)temp<<1 == 0)
    {
        len++;
    }
    System.out.println(len);

    if (unicodeChar.length == len) 
    {
        for(int i = 1 ; i < len; i++)
        {
            // Check if Most significant 2 bits in the byte are '10'
            // c0, in base 16, is 11000000 in binary
            // 10000000, in base 2, is 128 in decimal
            if( ( (int)unicodeChar[i]&0Xc0 )==128 )
            {
                continue;
            }
            else
            {
                return false;
            }
        }
        return true;
    }
    else
    {
        return false;
    }
}

The output I get is   
99
false  

Changed the conversion from char to byte array based on Chris Jester-Young’s comment.

Can someone point me to right direction

Thanks

Made some modifications based on input from Ted Hopp.
P.S:
I got the question from some forum and I think it wasn’t posted in correctly there, however I still decided to solve it and use it as is to prevent obfuscating it more, since I did not understand it completely either !

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T23:02:10+00:00Added an answer on May 22, 2026 at 11:02 pm

    Here’s an enterprise level solution for your enterprise level job:

    public static void main(String[] args) {
        if (args.length == 0 || args[0] == null || (args[0] = args[0].trim()).isEmpty()) {
            System.out.println("No argument passed or argument empty!");
            return;
        }
    
        String arg = args[0];
        System.out.println("arg: " + arg + ", arg len: " + arg.length());
    
        BitSet bs = new BitSet(arg.length());
        for (int i = 0; i < arg.length(); i++) {
            if (arg.charAt(i) == '1') {
                bs.set(i, true); 
            }
        }
        ByteBuffer bb = ByteBuffer.wrap(bs.toByteArray());
        Charset cs = Charset.forName("UTF-8");
        CharsetDecoder csd =
                cs.newDecoder().onMalformedInput(CodingErrorAction.REPORT).
                onUnmappableCharacter(CodingErrorAction.REPORT)
                ;
    
        try {
            CharBuffer cb = csd.decode(bb);
            String uns = cb.toString();
            System.out.println("Got unicode string of len " + uns.length() + ": " + uns + " from " + arg + " -- no errors!");
        } catch (CharacterCodingException cce) {
            System.out.println("Invalid UTF-8 unicode string! " + cce.getMessage());
        }
    }
    

    Verification:

    public static void test() {
        StringBuilder sb = new StringBuilder();
         byte[] byt = new String("stupid interview").getBytes();
         BitSet byt1 = fromByteArray(byt);
         for (int i = 0; i < byt1.size(); i++) {
             sb.append(byt1.get(i) ? "1" : "0");
         }
         String[] st = new String[1];
         st[0] = sb.toString();
         main(st);
    }
    
    public static BitSet fromByteArray(byte[] bytes) {
        BitSet bits = new BitSet();
        for (int i=0; i<bytes.length*8; i++) {
            if ((bytes[bytes.length-i/8-1]&(1<<(i%8))) > 0) {
                bits.set(i);
            }
        }
        return bits;
    }
    

    Output:

    11001110001011101010111000001110100101100010011000000100100101100111011000101110101001100100111001101110100101101010011011101110
    arg: 11001110001011101010111000001110100101100010011000000100100101100111011000101110101001100100111001101110100101101010011011101110, arg len: 128
    {0, 1, 4, 5, 6, 10, 12, 13, 14, 16, 18, 20, 21, 22, 28, 29, 30, 32, 35, 37, 38, 42, 45, 46, 53, 56, 59, 61, 62, 65, 66, 67, 69, 70, 74, 76, 77, 78, 80, 82, 85, 86, 89, 92, 93, 94, 97, 98, 100, 101, 102, 104, 107, 109, 110, 112, 114, 117, 118, 120, 121, 122, 124, 125, 126}
    Got unicode string of len 16: stupid interview from 11001110001011101010111000001110100101100010011000000100100101100111011000101110101001100100111001101110100101101010011011101110 -- no errors!
    
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