Question

I am using jquery.mobile-1.1.0 for a PhoneGap application. I am getting issue in button css. Jquery has its own button styling but I don’t want to use that and want have my own button css. I am also using few jQuery components like tabs, form-search that use jQuery-mobile css so I have to include it in my application.

Here is my html code:

    <div data-role="content">
    <div class="signup">
    <form action="#" id="loginForm">
    <fieldset>
    <ul>
    <li class="first">
    <label><span>Email*</span></label>
    <input name="loginemail" type="text" id="loginemail" class="input" placeholder="Enter Full Name"  />
    </li>

    <li>
    <label><span>Password*</span></label>
    <input name="loginpassword" id="loginpassword" type="text" class="input" placeholder="Pick A Password" />
    </li>

    <li>
    <input name="" type="submit" id="loginSubmit" class="button" value="Login"   />
    </li>
    </ul>

    </fieldset>
    </form>
    </div> <!-- signup- div -->
    </div><!-- - content -->
    </div> <!-- end login page -->

Source while doing inspect element in Firebug jQuery creates an outer layer against that button that eventually disturb my whole button css.

    <li><div aria-disabled="false" class="ui-btn ui-shadow ui-btn-corner-all 
    ui-fullsize ui-btn-block ui-btn-up-c" data-mini="false" data-inline="false" 
    data-theme="c" data-iconpos="" data-icon="" data-wrapperels="span"   
    data-iconshadow="true" data-shadow="true" data-corners="true">
    <span class="ui-btn-inner ui-btn-corner-all">
    <span class="ui-btn-text">Login</span>
    </span>
    <input aria-disabled="false" name="" id="loginSubmit" 
    class="button ui-btn-hidden" value="Login" type="submit"></div></li>

Here is my customized button class for css

  .button{ width:100% !important; height:69px !important; 
    float:left !important;
    font-size:24px !important;
    font-family:"MyriadPro-BoldCond_0",Arial, Helvetica, sans-serif !important; 
    color:#FFFFFF !important; text-align:center; 
    background:#ca2c00 !important; border:none !important; 
    background:-moz-linear-gradient(#ca2c00, #7a1a00) !important;
    background: -webkit-gradient(linear, left top, left bottom, from(#ca2c00), to(#7a1a00)) !important; 
   -pie-background: linear-gradient(#ca2c00, #7a1a00) !important;
    background: -o-linear-gradient(#ca2c00, #7a1a00) !important; 
   -moz-border-radius:0 0 7px 7px !important;
  -webkit-border-radius:0 0 7px 7px !important; 
   border-radius:0 0 7px 7px !important; behavior: url(PIE.htc) !important;   
   position:relative !important;
   cursor:pointer !important;} 

Please help. How can I stop jQuery from creating an outer shell around the button and allow it to pick my customized css. Thanks

Answer 1

In jquery mobile ,Input-based buttons and button elements are auto-enhanced, no data-role required. So you have two options to overcome this issue.

1. Edit the jquery mobile theme, or rather create a customized theme using Theme Roller. You can find the themeroller tool here.

2. Second option is to set data-role of the input button to none. Ex <input type=”button” data-role=”none” id=”btnId” class=”button”>.

Hope it helped you.

— MEJO