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Home/ Questions/Q 293271
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T06:15:23+00:00 2026-05-12T06:15:23+00:00

I am using the built-in module to insert a few instances, so they can

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I am using the built-in module to insert a few instances, so they can be accessed globally for debugging purposes. The problem with the __builtins__ module is that it is a module in a main script and is a dict in modules, but as my script depending on cases can be a main script or a module, I have to do this:

if isinstance(__builtins__, dict):
    __builtins__['g_frame'] = 'xxx'
else:
    setattr(__builtins__, 'g_frame', 'xxx')

Is there a workaround, shorter than this? More importantly, why does __builtins__ behave this way?

Here is a script to see this. Create a module a.py:

#module-a
import b
print 'a-builtin:',type(__builtins__)

Create a module b.py:

#module-b
print 'b-builtin:',type(__builtins__)

Now run python a.py:

$ python a.py 
b-builtin: <type 'dict'>
a-builtin: <type 'module'>
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  1. Editorial Team
    Editorial Team
    2026-05-12T06:15:24+00:00Added an answer on May 12, 2026 at 6:15 am

    I think you want the __builtin__ module (note the singular).

    See the docs:

    27.3. __builtin__ — Built-in objects

    CPython implementation detail: Most modules have the name __builtins__ (note the 's') made available as part of their globals. The value of __builtins__ is normally either this module or the value of this modules’s [sic] __dict__ attribute. Since this is an implementation detail, it may not be used by alternate implementations of Python.

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