Question

I am using this select

$sql1=" SELECT pole FROM Table1 WHERE dva='d'";

and it should return all for elements from the table ( because in the field “dva” they all have ‘d’) and using this function to do it

while( $row = sqlsrv_fetch_array($st)) {
 // echo $row[0]."<br />";
print_r($row);
}

here is the result I get, it starts from the second row and so on…

Array ( 
    [0] => testxz2 
    [pole] => testxz2 
) 
Array ( 
    [0] => some data 
    [pole] => some data 
) 
Array ( 
    [0] => some data 
    [pole] => some data 
) 

before I tried this and this got me the row number 1 and the other rows I got from the upper code,

   while($pole=sqlsrv_get_field($st,0)){echo $pole;}

Answer 1

Can u put the whole code before the fetch call

JUST edit the part before:

   if( sqlsrv_fetch( $st ) === false) {
     die( print_r( sqlsrv_errors(), true));

I think here is the error because you are fetching the first element and the second while u use to fetch all rows is missing the first because is already fetch… Try to use your while loop before the first fetch..