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Home/ Questions/Q 8335321
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T03:38:35+00:00 2026-06-09T03:38:35+00:00

I am working on a code, perhaps my approach is wrong working inside a

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I am working on a code, perhaps my approach is wrong working inside a “for” loop. Here is it:

for(var index = 0; index < $('div.parent').find('div.child').length; index++){
    var element[index] = $('div.parent').find('div.child').eq(index);
    // some code
}

The code should look like this:

for(var index = 0; index < $('div.parent').find('div.child').length; index++){
    var element1 = $('div.parent').find('div.child').eq(1);
    // some code with element1
    var element2 = $('div.parent').find('div.child').eq(2);
    // some code with element2   
}

Thanks for any suggestion.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T03:38:37+00:00Added an answer on June 9, 2026 at 3:38 am

    You can’t dynamically create a variable of a certain name. You will need to use an array:

    var elements = [];
    var children = $('div.parent').find('div.child');
    for(var index = 0; index < children.length; index++){
        elements.push( children.eq(index) );
        // some code
    }
    
    //reference by:
    elements[0];
    elements[1];
    // etc.
    

    Or even simpler with jQuery:

    var elements = $('div.parent').find('div.child').toArray();
    
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