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Home/ Questions/Q 6186835
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T01:57:24+00:00 2026-05-24T01:57:24+00:00

I am working on a program that uses mpi (openmpi 1.4.3) and pthreads, working

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I am working on a program that uses mpi (openmpi 1.4.3) and pthreads, working in c++ under linux.

some of the mpi nodes have a queuing system implemented with pthreads.
Idea is simple one thread adding elements into queue, and few other “working” threads picking up objects and doing their job on them (not a rocket science).

Please consider 2 examples of my working threads which picking up elements.
First example working fine unless -O3 optimization is specified. In that case it starts to endlessly looping without picking up anything.

    while (true){
        if (t_exitSignal[tID]){
            dorun = false;
            break;
        }

        //cout<<"w8\n";

        //check if queue has some work for us
        if (!frame_queue->empty()){

            //try to get lock and recheck that queue no empty
            pthread_mutex_lock( &mutex_frame_queue );

            if (!frame_queue->empty()){
                cout<<"Pickup "<<tID<<endl;
                con = frame_queue->front();
                frame_queue->pop();
                t_idling[tID] = false;
                pthread_mutex_unlock( &mutex_frame_queue );
                break;
            }

            pthread_mutex_unlock( &mutex_frame_queue );
        }

    }

Now consider this one, exactly the same code, except mutex gettimg locked before I checking for queue->empthy. This work works fine for all levels of optimization.

    while (true){
        if (t_exitSignal[tID]){
            dorun = false;
            break;
        }
        //cout<<"w8\n";

        //try to get lock and recheck that queue no empty
        pthread_mutex_lock( &mutex_frame_queue );

        //check if queue has some work for us
        if (!frame_queue->empty()){

                cout<<"Pickup "<<tID<<endl;
                con = frame_queue->front();
                frame_queue->pop();
                t_idling[tID] = false;
                pthread_mutex_unlock( &mutex_frame_queue );
                break;

        }
        pthread_mutex_unlock( &mutex_frame_queue );

    }

Just in case it make a difference this is how I populate queue from other thread

                    pthread_mutex_lock( &mutex_frame_queue );
            //adding the same contianer into queue to make it available for threads
            frame_queue->push(*cursor);
            pthread_mutex_unlock( &mutex_frame_queue );

My question is: why first example of code stop working why I compiling with -O3 option ?
Any other suggestion for the queuing system ?

Thanks a lot!

SOLUTION: This is what I come up with at the end. Seems to work much better than either of the methods above. (just in case someone interested 😉

    while (true){

        if (t_exitSignal[tID]){

            dorun = false;
            break;
        }
        //try to get lock and check that queue no empty
        pthread_mutex_lock( &mutex_frame_queue );

        if (!frame_queue->empty()){

            con = frame_queue->front();
            frame_queue->pop();
            t_idling[tID] = false;
            pthread_mutex_unlock( &mutex_frame_queue );
            break;
        }else{

            pthread_cond_wait(&conf_frame_queue, &mutex_frame_queue);
            pthread_mutex_unlock( &mutex_frame_queue );
        }




    }

Adding

        pthread_mutex_lock( &mutex_frame_queue );

        //adding the same contianer into queue to make it available for threads
        frame_queue->push(*cursor);
        //wake up any waiting threads
        pthread_cond_signal(&conf_frame_queue);
        pthread_mutex_unlock( &mutex_frame_queue )
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T01:57:25+00:00Added an answer on May 24, 2026 at 1:57 am

    I’m guessing you are seeing a bug based on assumptions about instruction ordering when you check if the queue is empty – when you turn up the optimization the ordering changes and it breaks because the mutex you have hasn’t put up a memory barrier protecting this from occurring.

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