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Home/ Questions/Q 8284507
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T11:07:54+00:00 2026-06-08T11:07:54+00:00

I am writing some PHP code that’s kind of like this: foreach($filter[1] as $reject){

  • 0

I am writing some PHP code that’s kind of like this:

foreach($filter[1] as $reject){
        $reject_processed = preg_replace('~\s~','',strtolower($filter[1][$reject]));
        if(array_key_exists($reject_processed,$list_of_common_replacements)){
            $filter[0][] = $list_of_common_replacements[$reject_processed];
            $filter[1] = array_splice($filter[1],$reject,1)
        }

    }

It’s supposed to search through a list of rejected values (filter[1]), find if a replacement exists, then (if so) add the replacement to the list of good values (filter[0]) while deleting the fixed value from the reject list.

Will deleting values from an array that’s the main subject of a foreach(), inside the foreach(), cause problems with this?

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  1. Editorial Team
    Editorial Team
    2026-06-08T11:07:56+00:00Added an answer on June 8, 2026 at 11:07 am

    No. foreach creates a copy of the array. Consider the following code:

    $arr = array(1,2,3,4,5);
    foreach($arr as $k=>$v) {
        if($v==1) {
            unset($arr);
        }
        echo $v;
    }
    

    Even though we unset the entire original array in the very first iteration, this would still print 12345.

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