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Home/ Questions/Q 8155449
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T16:40:20+00:00 2026-06-06T16:40:20+00:00

I can’t understand what is happening in my code: for (NSMutableDictionary *dict in jsonResponse)

  • 0

I can’t understand what is happening in my code:

 for (NSMutableDictionary *dict in jsonResponse) {


     NSString *days = [dict objectForKey:@"dayOfTheWeek"];

     NSArray *arrayDays = [days componentsSeparatedByString:@" "];

     NSLog(@"la var %@ size %lu", days, sizeof(arrayDays));


     for(int i = 0; i<sizeof(arrayDays); i++){

        NSLog(@"el dia %@",[arrayDays objectAtIndex:i]);

     }
}

What I get in log:

2012-07-02 10:06:57.191 usualBike[1342:f803] var M T W T F size 4
2012-07-02 10:06:57.191 usualBike[1342:f803] day M
2012-07-02 10:06:57.192 usualBike[1342:f803] day T
2012-07-02 10:06:57.192 usualBike[1342:f803] day W
2012-07-02 10:06:57.193 usualBike[1342:f803] day T
2012-07-02 10:06:57.193 usualBike[1342:f803] var S S size 4
2012-07-02 10:06:57.194 usualBike[1342:f803] day S
2012-07-02 10:06:57.194 usualBike[1342:f803] day S

And crashes, because position 3 doesn’t exist.

Why the size is not changing the second time? it should be 1.

Thank you in advance

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T16:40:21+00:00Added an answer on June 6, 2026 at 4:40 pm

    sizeof(theArray) calculates the size of the datatype, see Wikipedia.
    [theArray count] and theArray.Count return the count of objects in the array.

    Replace both occurrences of sizeof(arrayDays) by arrayDays.Count.

    Note: You can also loop the array using the following:

    for (NSString* theValue in arrayDays) {
        NSLog(@"el dia %@",theValue);
    }
    
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