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Home/ Questions/Q 8248535
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T23:13:11+00:00 2026-06-07T23:13:11+00:00

I currently have this macro #define bind(OBJECT, ROLE) \ assert( sizeof(*ROLE) == 1 );

  • 0

I currently have this macro

#define bind(OBJECT, ROLE) \
assert( sizeof(*ROLE) == 1 ); \
ROLE = reinterpret_cast<decltype(ROLE)>(OBJECT);

It is causing some name clashing issues so I’d like to move this into a templated function like

template<typename T1, typename T2>
void bind(T1 obj, T2 r) {
    assert( sizeof(*r) == 1 );
    r = reinterpret_cast<T2>(obj);
};

However, I suspect that this is not possible, but would like to be confirmed on this? In order to change r, I must have a pointer to a pointer?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T23:13:12+00:00Added an answer on June 7, 2026 at 11:13 pm

    You will need at least need a reference:

    template<typename T1, typename T2>
    void bind(T1 obj, T2& r)
    {
        assert( sizeof(*r) == 1 );
        r = reinterpret_cast<T2>(obj);
    }
    

    Another option is to use a template conversion operator. Then you can call with the syntax:

    ROLE = bind(OBJ);
    

    The code would be more-or-less like this:

    template<typename T1> class auto_converter
    {
        const T1& value;
    public:
        auto_converter(const T1& v) : value(v) {}
    
        // template conversion operator
        template<typename T2>
        operator T2() const
        {
            assert(sizeof (*T2()) == 1);
            return reinterpret_cast<T2>(value);
        }
    };
    
    template<typename T1>
    autoconverter<T1> bind(const T1& obj) { return obj; }
    
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