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Home/ Questions/Q 8267559
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T05:34:36+00:00 2026-06-08T05:34:36+00:00

I feel like this has a very simple solution, but I am trying to

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I feel like this has a very simple solution, but I am trying to get this to work for probably too long now.

I’ve made a function to render an image, atleast that’s what it’s supposed to do, but it doesn’t.

function renderAD(entries) {
    var o = '';
    $.each(entries, function(i, v) {
        o +="<img src=" +v.image +"/>";
    });
    $("#adplace").html(o);    
}

I checked that v.image refers to http://allroundcars.nl/logo-ijsselmondenieuws.png, which is the image I want to load. But all I see is a '?' image (image not found).

What am I doing wrong? Any help is appreciated,

Thanks

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  1. Editorial Team
    Editorial Team
    2026-06-08T05:34:39+00:00Added an answer on June 8, 2026 at 5:34 am

    Try replacing your each with:

    $(entries).each(function(i, v) {
        o +='<img src="' + v.image + '"/>';
    });
    

    Update: to add an <a> around it:

    o +='<a href="' + v.link + '"><img src="' + v.image + '"/></a>';
    
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