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Home/ Questions/Q 400469
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T16:56:39+00:00 2026-05-12T16:56:39+00:00

I found the below code through Google. It almost does what I want it

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I found the below code through Google. It almost does what I want it to do, except it doesn’t provide a way to indicate the precision like ‘%.*f’ does in C-type format strings. Also, it doesn’t provide anything further than 5 decimal places. Am I going to have to stick with C strings and snprintf?

#include <string>
#include <sstream>
#include <iostream>

template <class T>
std::string to_string(T t, std::ios_base & (*f)(std::ios_base&))
{
  std::ostringstream oss;
  oss << f << t;
  return oss.str();
}

int main()
{
  std::cout<<to_string<double>(3.1415926535897931, std::dec)<<std::endl;
  return 0;
} 
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T16:56:40+00:00Added an answer on May 12, 2026 at 4:56 pm

    You want to use the std::setprecision manipulator:

    int main()
    {
        std::cout << std::setprecision(9) << to_string<long>(3.1415926535897931, std::dec)
                  << '\n';
        return 0;
    }
    
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