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Home/ Questions/Q 1030105
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T12:38:52+00:00 2026-05-16T12:38:52+00:00

I got this function to get a cssPath : var cssPath = function (el)

  • 0

I got this function to get a cssPath :

var cssPath = function (el) {
  var path = [];

  while (
    (el.nodeName.toLowerCase() != 'html') && 
    (el = el.parentNode) &&
    path.unshift(el.nodeName.toLowerCase() + 
      (el.id ? '#' + el.id : '') + 
      (el.className ? '.' + el.className.replace(/\s+/g, ".") : ''))
  );
  return path.join(" > ");
}
console.log(cssPath(document.getElementsByTagName('a')[123]));

But i got something like this :

html > body > div#div-id > div.site > div.clearfix > ul.choices > li

But to be totally right, it should look like this :

html > body > div#div-id > div.site:nth-child(1) > div.clearfix > ul.choices > li:nth-child(5)

Did someone have any idea to implement it simply in javascript ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T12:38:53+00:00Added an answer on May 16, 2026 at 12:38 pm

    To always get the right element, you will need to use :nth-child() or :nth-of-type() for selectors that do not uniquely identify an element. So try this:

    var cssPath = function(el) {
        if (!(el instanceof Element)) return;
        var path = [];
        while (el.nodeType === Node.ELEMENT_NODE) {
            var selector = el.nodeName.toLowerCase();
            if (el.id) {
                selector += '#' + el.id;
            } else {
                var sib = el, nth = 1;
                while (sib.nodeType === Node.ELEMENT_NODE && (sib = sib.previousSibling) && nth++);
                selector += ":nth-child("+nth+")";
            }
            path.unshift(selector);
            el = el.parentNode;
        }
        return path.join(" > ");
    }
    

    You could add a routine to check for unique elements in their corresponding context (like TITLE, BASE, CAPTION, etc.).

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