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Home/ Questions/Q 965469
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T02:00:15+00:00 2026-05-16T02:00:15+00:00

I guess the best thing to do is to show the code what I’m

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I guess the best thing to do is to show the code what I’m doing at the result:

This works:

if (sqlite3_column_text(statement, 0)) {
    [marker setObject:[NSNumber numberWithInt: sqlite3_column_int(statement, 0)] forKey:@"id"];
}

This always returns false for the if statement:

if (sqlite3_column_int(statement, 0)) {
    [marker setObject:[NSNumber numberWithInt: sqlite3_column_int(statement, 0)] forKey:@"id"];
}

This returns an incorrect result for the column:

if (sqlite3_column_text(statement, 0)) {
    [marker setObject:[NSNumber numberWithInt: sqlite3_column_text(statement, 0)] forKey:@"id"];
}

Any idea whats going on?

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  1. Editorial Team
    Editorial Team
    2026-05-16T02:00:15+00:00Added an answer on May 16, 2026 at 2:00 am

    You should get the number of columns returned before you try to access the value of the column.

    int count = sqlite3_column_count (statement);
    

    When you call sqlite3_column_int(), it returns the integer value of the column. What if that value is zero? You can’t tell the difference between a valid zero result and a null value for that column. You can test if a column has a null with

    sqlite3_column_type () == SQLITE_NULL;
    

    Also, Obj-C does not automatically convert different types, so numberWithInt: sqlite3_column_text will of course give garbage results. What sqlite3_column_text() returns is a pointer to a C string, which is an address in memory where the string resides. I’m guessing you’re expecting it to somehow convert the string to an integer? That doesn’t happen in C.

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