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Home/ Questions/Q 5991961
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T23:27:47+00:00 2026-05-22T23:27:47+00:00

I happens to read this http://code.google.com/speed/articles/optimizing-php.html It claims that this code $description = strip_tags($_POST[‘description’]);

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I happens to read this http://code.google.com/speed/articles/optimizing-php.html

It claims that this code

$description = strip_tags($_POST['description']);
echo $description;

should be optimized as below

echo strip_tags($_POST['description']);

However, in my understanding, assignment operation in PHP is not necessarily create a copy in memory.

This only have one copy of “abc” in memory.

$a = $b = "abc";

It consumes more memory only when one variable is changed.

$a = $b = "abc";
$a = "xyz";

Is that correct?

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  1. Editorial Team
    Editorial Team
    2026-05-22T23:27:48+00:00Added an answer on May 22, 2026 at 11:27 pm

    should be optimized as below

    It’s only a good idea if you don’t need to store it, thereby avoiding unnecessary memory consumption. However, if you need to output the same thing again later, it’s better to store it in a variable to avoid a another function call.

    Is that correct?

    Yes. It’s called copy-on-write.

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