Question

i have a a couple c++ interfaces like this:

struct IThese {
virtual void doThesethings() = 0;
}

struct IThose : public IThese {
virtual void doThoseOtherThings() = 0;
}

Notice that IThose implement their own method, but also implements those from the other interface, so the idea is that implementors of IThose will need to implement both

Question: do i need to redeclare doThesethings in IThose?

if not, what would happen if i did it? would it shadow the IThese method?

Answer 1

Presently class IThose is abstract class** and you don’t have to redeclare doTheseThings() inside it. You can choose to implement doTheseThings() inside class IThose.

If doThesethings() is implemented in class IThose, then it’s child class (which derive IThose) may or may not implement it. But they must implement doThoseOtherThings(), if they don’t want to be abstract.

**abstract class: contains at least one pure virtual method within it or via its base class