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Home/ Questions/Q 8204139
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T07:48:13+00:00 2026-06-07T07:48:13+00:00

I have a Counter object that looks like this: counts = Counter({‘foo’: 10, ‘baz’:

  • 0

I have a Counter object that looks like this:

counts = Counter({'foo': 10, 'baz': 5, 'biff': 3, 'bonk': 1})

for k, v in counts.items(): 
    print k, v

    bonk 1
    foo 10
    baz 5
    biff 3

What is the best way to iterative over the Counter object by descending frequency of the values? Speed is important. There is an OrderCounter class in the docs, but I was looking for something simpler.

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  1. Editorial Team
    Editorial Team
    2026-06-07T07:48:16+00:00Added an answer on June 7, 2026 at 7:48 am

    Use Counter.most_common()

    >>> counts = Counter({'foo': 10, 'baz': 5, 'biff': 3, 'bonk': 1})
    >>> for k, v in counts.most_common():
        print k, v
    foo 10
    baz 5
    biff 3
    bonk 1
    
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