Question

I have a framework function which expects an object and a member function pointer (callback), like this:

do_some_work(Object* optr, void (Object::*fptr)()); // will call (optr->*fptr)()

How can I pass a lambda expression to it? Want to do somethink like this:

class MyObject : public Object
{
    void mystuff()
    {
        do_some_work(this, [](){ /* this lambda I want to pass */ });
    }
};

The meaning of it all is to not clutter the interface of MyObject class with callbacks.

UPD
I can improve do_some_work in no way because I don’t control framework and because actually it isn’t one function, there’re hundreds of them. Whole framework is based on callbacks of that type. Common usage example without lambdas:

typedef void (Object::*Callback)();
class MyObject : public Object
{
    void mystuff()
    {
        do_some_work(this, (Callback)(MyClass::do_work));
    }
    void do_work()
    {
        // here the work is done
    }
};

SOLUTION Here’s my solution based on Marcelo’s answer:

class CallbackWrapper : public Object
{
    fptr fptr_;
public:
    CallbackWrapper(void (*fptr)()) : fptr_(fptr) { }
    void execute()
    {
        *fptr_();
    }
};

class MyObject : public Object
{
    void mystuff()
    {
        CallbackWrapper* do_work = new CallbackWrapper([]()
        {
           /* this lambda is passed */
        });
        do_some_work(do_work, (Callback)(CallbackWrapper::execute));
    }
};

Since we create the CallbackWrapper we can control it’s lifetime for the cases where the callback is used asynchonously. Thanks to all.

Answer 1

This is impossible. The construct (optr->*fptr)() requires that fptr be a pointer-to-member. If do_some_work is under your control, change it to take something that’s compatible with a lambda function, such as std::function<void()> or a parameterised type. If it’s a legacy framework that isn’t under your control, you may be able to wrap it, if it’s a function template, e.g.:

template <typename Object>
do_some_work(Object* optr, void (Object::*fptr)());

Then, you can implement a wrapper template:

template <typename F>
void do_some_work(F f) {
    struct S {
        F f;
        S(F f) : f(f) { }
        void call() { f(); delete this; }
    };
    S* lamf = new S(f);
    do_some_work(lamf, &S::call);
}

class MyObject // You probably don't need this class anymore.
{
    void mystuff()
    {
        do_some_work([](){ /* Do your thing... */ });
    }
};

Edit: If do_some_work completes asynchronously, you must allocate lamf on the heap. I’ve amended the above code accordingly, just to be on the safe side. Thanks to @David Rodriguez for pointing this out.