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Home/ Questions/Q 3723086
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T06:08:33+00:00 2026-05-19T06:08:33+00:00

I have a model with two many-to-many relationships. Play framework creates the relationship tabel

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I have a model with two many-to-many relationships. Play framework creates the relationship tabel for me, but none of the ids are nullable, resulting with me unable to get my code to work.

Play framework returns
PersistenceException occured : insert into Costumer_Item (customersWhoIgnored_id, ignoredItems_id) values (?, ?)

19:20:54,530 ERROR ~ Field 'customersWhoBought_id' doesn't have a default value
19:20:54,531 ERROR ~ Could not synchronize database state with session
org.hibernate.exception.GenericJDBCException: Could not execute JDBC batch update

The code is Item.java:

@Entity
public class Item extends Model {
  @ManyToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, mappedBy = "ownedItems")
  public List<Costumer> customersWhoBought;

  @ManyToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, mappedBy = "ignoredItems")
  public List<Costumer> customersWhoIgnored;
}

Customer.java:

@Entity
public class Customer extends Model {
  @Column(nullable = true)
  @ManyToMany(cascade = CascadeType.ALL)
  public List<Item> ownedItems;

  @Column(nullable = true)
  @ManyToMany(cascade = CascadeType.ALL)
  public List<Item> ignoredItems;

}

How do I get many @ManyToMany relationships to work?

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  1. Editorial Team
    Editorial Team
    2026-05-19T06:08:34+00:00Added an answer on May 19, 2026 at 6:08 am

    I think both relationships use the same join table with default name Costumer_Item, which causes confusion. You need to specify different names manually:

    @ManyToMany(cascade = CascadeType.ALL)
    @JoinTable(name = "CostumerToOwnedItems")
    public List<Item> ownedItems;
    
    @ManyToMany(cascade = CascadeType.ALL)
    @JoinTable(name = "CostumerToIgnoredItems")
    public List<Item> ignoredItems;
    
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