Question

I have a page that has 4 tables. Initially when the page is loaded, it shows 1 & 2. Thats working fine. On Post back(When Submit is clicked), it should show 3 & 4. Even thats working fine(code shown here). When the submit is clicked again, it has to call updatePaymentInfo() and redirect. Is there something to write as a condition to call UpdatepaymentInfo() because when submit is clicked, it is taking as an other postback and showing me 3 & 4 again.

protected void imgbtnSubmit_Click(object sender, ImageClickEventArgs e)
{
    try
    {
        if (Page.IsPostBack)
        {
            trtest.Visible = false;
            trCCandBilling.Visible = true;
            trtest2.Visible = true;
        }
        else
        {
            UpdatePaymentInfo();
            Response.Redirect(ApplicationData.URL_MERCHANT_ACCOUNT_HOME, true);
        }
    }
 }

Answer 1

My thought on the easiest way to do this is to have two image submit buttons in the same place. Button A is the one you already have button B is a new one that whose submit handler runs UpdatepaymentInfo and redirects.

Button B starts off invisible while button A is visible. When Button A is clicked in addition to the visibility changes you hide button a and show button B. Then when they click button B the right stuff happens.

Its not that elegant though.

Another solution might be storing values in the page to indicate the current page state that you can then check on button click.